Linkage map distance of 1 cM (centimorgan) corresponds to:
- 1% recombination frequency between two markers in offspring
- Random
- 1 chromosome
- 1 mutation
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Correct answer: A. 1% recombination frequency between two markers in offspring
1 cM = 1% recombination frequency.
**In human genome:** 1 cM ≈ 1 Mb on average (varies by location and sex).
Maximum linkage map distance = 50 cM (genes appear unlinked).
Used to construct genetic maps before physical sequencing.