alleryLinkage map distance of 1 cM (centimorgan) corresponds to:
A1% recombination frequency between two markers in offspring
BRandom
C1 chromosome
D1 mutation
Answer & Solution
Correct answer: A. 1% recombination frequency between two markers in offspring
1 cM = 1% recombination frequency.
**In human genome:** 1 cM ≈ 1 Mb on average (varies by location and sex).
Maximum linkage map distance = 50 cM (genes appear unlinked).
Used to construct genetic maps before physical sequencing.
Keep practising Unit 5C: Non-Mendelian Genetics & Population Transmission
Browse all Unit 5C: Non-Mendelian Genetics & Population Transmission questions for AP Biology, or explore more Biology topics.
Related questions
Which of the following is **not** a stop codon?The semiconservative nature of DNA replication was experimentally proved by:The F₂ **genotypic** ratio in Mendel's monohybrid cross is:In Mendel's monohybrid cross between true-breeding tall (TT) and dwarf (tt) plants, the F₂Mendel conducted his hybridisation experiments on which plant?In the Watson-Crick double helix, adenine pairs with thymine via how many hydrogen bonds?In birds, the sex-determination mechanism is:Down syndrome in humans is caused by