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In Mendel's dihybrid cross with round-yellow and wrinkled-green seeds, what is the phenotypic ratio of the F2 generation?
A9 : 3 : 3 : 1
B3 : 1
C1 : 2 : 1
D1 : 1 : 1 : 1
Answer & Solution
Correct answer: A. 9 : 3 : 3 : 1
1. Cross round-yellow (RRYY) with wrinkled-green (rryy); F1 is all RrYy round-yellow.
2. Self the F1 RrYy x RrYy; each parent makes four gamete types RY, Ry, rY, ry.
3. The 4x4 Punnett square gives 9 round-yellow, 3 round-green, 3 wrinkled-yellow, 1 wrinkled-green.
4. So the dihybrid phenotypic ratio is 9 : 3 : 3 : 1, option A.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 18 Genetics "Dihybrid Cross", p.271_
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