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MHT-CET Magnetic Fields due to Electric Current — practice questions

Explore 43 free Magnetic Fields due to Electric Current questions in MHT-CET Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Magnetic Fields due to Electric Current questions and exercises with answers

Showing questions 1–30 of 43.

The Biot-Savart law gives the field of a current element as varying with distance r as:Read the answer and worked solution →A long straight wire carries 5 A. What is the magnetic field at 10 cm from it?Read the answer and worked solution →Doubling the distance from a long straight current-carrying wire changes its magnetic field to:Read the answer and worked solution →The magnetic field at the centre of a circular loop of radius R carrying current I is:Read the answer and worked solution →A circular arc of radius R subtends angle theta at its centre and carries current I. The field at the centre is:Read the answer and worked solution →The force per unit length between two long parallel wires with currents I1, I2 at distance d is:Read the answer and worked solution →Two parallel wires carry 10 A and 5 A, 5 cm apart. The force per metre is:Read the answer and worked solution →The SI ampere is defined using parallel wires 1 m apart in vacuum with a force per metre of:Read the answer and worked solution →Doubling the separation of two parallel current-carrying wires changes the force between them to:Read the answer and worked solution →Two wires 0.2 m apart carry 20 A and 30 A. What is the force per metre?Read the answer and worked solution →By Ampere's law, the closed line integral of B equals:Read the answer and worked solution →In magnetostatics, Ampere's law plays the role that which law plays in electrostatics?Read the answer and worked solution →The Biot-Savart law in magnetostatics is analogous to which law in electrostatics?Read the answer and worked solution →From which law can Ampere's law be derived?Read the answer and worked solution →Three wires carry 2 A and 3 A out of a page and 4 A into it, all inside a loop. The integral of B.dl is:Read the answer and worked solution →A wire outside an Amperian loop contributes what to the closed line integral of B?Read the answer and worked solution →An ideal solenoid has n turns per unit length and current i. Its inside field is:Read the answer and worked solution →The magnetic field outside an ideal long solenoid is:Read the answer and worked solution →A 0.5 m solenoid has 400 turns and carries 2.5 A. The inside field is about:Read the answer and worked solution →A solenoid carrying 5 A has a field 6.28 x 10^-3 T. How many turns per metre does it have?Read the answer and worked solution →Doubling the current in a solenoid while halving its turns per unit length makes B:Read the answer and worked solution →Inside a long ideal solenoid the magnetic field is directed:Read the answer and worked solution →A toroid is best described as:Read the answer and worked solution →The magnetic field lines inside a toroid form:Read the answer and worked solution →In a coaxial cable with equal opposite currents, the field outside the outer conductor is:Read the answer and worked solution →In a coaxial cable, the field between the core (a) and outer shell (b) is:Read the answer and worked solution →At a point on the line along a current element, the field of that element is:Read the answer and worked solution →The field of a current element is largest at a point where the angle between dl and r is:Read the answer and worked solution →The direction of dB due to a current element is given by the vector:Read the answer and worked solution →A wire carries 20 A. At what distance is its field 4 x 10^-5 T?Read the answer and worked solution →

Worked practice questions

The Biot-Savart law gives the field of a current element as varying with distance r as:

  1. 1/r^3
  2. 1/r
  3. r^2
  4. 1/r^2
Show answer and solution

Correct answer: D. 1/r^2

The magnitude of dB is proportional to Idl sin(theta)/r^2, so it is an inverse square law in r.

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A long straight wire carries 5 A. What is the magnetic field at 10 cm from it?

  1. 1 x 10^-6 T
  2. 5 x 10^-6 T
  3. 1 x 10^-5 T
  4. 2 x 10^-5 T
Show answer and solution

Correct answer: C. 1 x 10^-5 T

B = mu0 I/(2 pi r) = 2 x 10^-7 x 5/0.1 = 1 x 10^-5 T.

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Doubling the distance from a long straight current-carrying wire changes its magnetic field to:

  1. four times
  2. double
  3. one fourth
  4. half
Show answer and solution

Correct answer: D. half

For a long wire B = mu0 I/(2 pi r), so B is inversely proportional to r and halves when r doubles.

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