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Three wires carry 2 A and 3 A out of a page and 4 A into it, all inside a loop. The integral of B.dl is:

A1.26 x 10^-6 T m
B1.13 x 10^-5 T m
C4.0 x 10^-7 T m
D2.5 x 10^-6 T m
Answer & Solution
Correct answer: A. 1.26 x 10^-6 T m
Net enclosed current is 2 + 3 - 4 = 1 A, so the integral is 4 pi x 10^-7 x 1 = 1.26 x 10^-6 T m.
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