alleryStart learning →In a coaxial cable with equal opposite currents, the field outside the outer conductor is:
Aexactly zero
Bmu0 I/(2 pi r)
Cmu0 I/(2r)
Dmu0 I/(4 pi r)
Answer & Solution
Correct answer: A. exactly zero
Outside both conductors the net enclosed current is I - I = 0, so Ampere's law gives B = 0.
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