alleryStart learning →A wire outside an Amperian loop contributes what to the closed line integral of B?
Amu0 times that current
BNo contribution at all
Ctwice mu0 times I
Dmu0 times I over two
Answer & Solution
Correct answer: B. No contribution at all
A current not enclosed by the loop adds nothing to the net enclosed current; its field contributions cancel over the full loop.
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