alleryStart learning →A circular arc of radius R subtends angle theta at its centre and carries current I. The field at the centre is:
Amu0 I/(2 pi R)
Bmu0 I theta/(4 pi R)
Cmu0 I theta/(2R)
Dmu0 I/(4 pi R theta)
Answer & Solution
Correct answer: B. mu0 I theta/(4 pi R)
Integrating dB = mu0 I dl/(4 pi R^2) over arc length R theta gives B = mu0 I theta/(4 pi R), with theta in radians.
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