alleryStart learning →The magnetic field at the centre of a circular loop of radius R carrying current I is:
Amu0 I/(2 pi R)
Bmu0 I/(2R)
Cmu0 I/(4R)
D2 mu0 I/R
Answer & Solution
Correct answer: B. mu0 I/(2R)
Every element dl is perpendicular to the radius, so integrating the Biot-Savart law over the full circle gives B = mu0 I/(2R).
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