alleryStart learning →The force per unit length between two long parallel wires with currents I1, I2 at distance d is:
Amu0 I1 I2 d/(2 pi)
Bmu0 I1 I2/(2 pi d)
Cmu0 I1 I2/(2 d)
Dmu0 (I1 + I2)/(2 pi d)
Answer & Solution
Correct answer: B. mu0 I1 I2/(2 pi d)
The field of wire 1 at wire 2 is mu0 I1/(2 pi d), and the force per length on wire 2 is I2 times this.
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