alleryStart learning →In a coaxial cable, the field between the core (a) and outer shell (b) is:
Amu0 I/(4 pi r)
Bmu0 I/(2 pi r)
Cmu0 I/(2 r)
Dmu0 I a/(2 pi r)
Answer & Solution
Correct answer: B. mu0 I/(2 pi r)
A circle of radius r between a and b encloses only the core current I, so B = mu0 I/(2 pi r).
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