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KCET Application of Derivatives — practice questions

Explore 52 free Application of Derivatives questions in KCET Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Application of Derivatives questions and exercises with answers

Showing questions 1–30 of 52.

Slope of tangent to y = f(x) at point (a, f(a)) is:Read the answer and worked solution →Slope of normal line to y = f(x) at x = a (if f'(a) ≠ 0):Read the answer and worked solution →At a stationary point of f, derivative f' equals:Read the answer and worked solution →Function f is INCREASING on interval (a, b) if:Read the answer and worked solution →Local maximum of f at x = c (if f'(c) = 0):Read the answer and worked solution →Mean Value Theorem says that for continuous f on [a, b] differentiable on (a, b), there exists c ∈ (a, b) with:Read the answer and worked solution →For y = x³ - 3x² + 2, find critical points:Read the answer and worked solution →Point of inflection of curve y = f(x) is where:Read the answer and worked solution →For y = sin x, find dy/dx at x = π/3:Read the answer and worked solution →Approximation by differentials: Δy ≈ f'(x) Δx. Using this, sqrt(25.5) is approximately:Read the answer and worked solution →Rate of change of area of a circle (A = πr²) with respect to radius:Read the answer and worked solution →If two functions f and g satisfy f'(x) = g'(x) for all x on an interval, then:Read the answer and worked solution →Rate of change of volume V = (4/3)πr³ of a sphere with radius:Read the answer and worked solution →Linear approximation of f(x) near x = a:Read the answer and worked solution →A spherical balloon's volume increases at 30 cm³/s. At r = 5 cm, how fast is the radius increasing?Read the answer and worked solution →Find equation of tangent to y = x² - 1 at point (2, 3):Read the answer and worked solution →Maximum area of a rectangle inscribed in a semicircle of radius R (base on diameter):Read the answer and worked solution →Use L'Hôpital's rule: lim_(x→0) (sin x - x)/x³ =Read the answer and worked solution →For f(x) = x² ln x on (0, ∞), find x where f has local minimum:Read the answer and worked solution →A 5 m ladder slides down a wall. Bottom moves outward at 1 m/s. Speed of top when bottom is 3 m from wall:Read the answer and worked solution →For y = e^x − x, find values where tangent is horizontal:Read the answer and worked solution →For f(x) = x³ - 3x² + 4, the function is increasing on intervals:Read the answer and worked solution →Find minimum value of f(x) = (sin x)² + (cos x)² + 2 (sin x)(cos x):Read the answer and worked solution →Volume of cylinder inscribed in sphere of radius R, expressed using h (height of cylinder):Read the answer and worked solution →Concavity test: f(x) = e^x is:Read the answer and worked solution →Find the rate at which the surface area of a balloon (sphere) is changing when radius is 10 cm and dr/dt = 0.1 cm/s:Read the answer and worked solution →Order the second derivative testRead the answer and worked solution →What does the sign of f ′(x) tell you?Read the answer and worked solution →Complete the definition of a critical pointRead the answer and worked solution →Order the first derivative testRead the answer and worked solution →

Worked practice questions

Slope of tangent to y = f(x) at point (a, f(a)) is:

  1. f(a)
  2. 1/f'(a)
  3. f''(a)
  4. f'(a) (derivative at the point)
Show answer and solution

Correct answer: D. f'(a) (derivative at the point)

Derivative f'(a) is the slope of the tangent line at x = a. **Equation of tangent:** y - f(a) = f'(a)(x - a).

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Slope of normal line to y = f(x) at x = a (if f'(a) ≠ 0):

  1. -1/f'(a) (perpendicular to tangent)
  2. f'(a)
  3. 1/f(a)
  4. -f'(a)
Show answer and solution

Correct answer: A. -1/f'(a) (perpendicular to tangent)

Normal ⊥ tangent. Slope of normal = -1/f'(a).

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At a stationary point of f, derivative f' equals:

  1. x
  2. f
  3. 0
  4. 1
Show answer and solution

Correct answer: C. 0

**Stationary (or critical) point:** f'(x) = 0. Could be local max, local min, or saddle (inflection). Use higher derivatives to classify.

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