allerySlope of normal line to y = f(x) at x = a (if f'(a) ≠ 0):
A-1/f'(a) (perpendicular to tangent)
Bf'(a)
C1/f(a)
D-f'(a)
Answer & Solution
Correct answer: A. -1/f'(a) (perpendicular to tangent)
Normal ⊥ tangent.
Slope of normal = -1/f'(a).
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