Find minimum value of f(x) = (sin x)² + (cos x)² + 2 (sin x)(cos x):
A1 + sin(2x) so min = 0
B2
C-1
D0
Answer & Solution
Correct answer: A. 1 + sin(2x) so min = 0
We have f(x) = 1 + 2 sin x cos.
So x = 1 + sin(2x).
Range of sin(2x) is [-1, 1].
**So f ranges from 0 to 2. Minimum value is 0.**
Keep practising Unit 4-5: Applications of Derivatives & Curve Sketching
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