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Find minimum value of f(x) = (sin x)² + (cos x)² + 2 (sin x)(cos x):
A1 + sin(2x) so min = 0
B2
C-1
D0
Answer & Solution
Correct answer: A. 1 + sin(2x) so min = 0
f(x) = 1 + 2 sin x cos x = 1 + sin(2x). Range of sin(2x) is [-1, 1]. So f ranges from 0 to 2. Minimum value is 0.
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