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For y = e^x − x, find values where tangent is horizontal:
ANever
Bx = -1
Cx = 1
Dx = 0 (where y' = e^x - 1 = 0)
Answer & Solution
Correct answer: D. x = 0 (where y' = e^x - 1 = 0)
y' = e^x - 1 = 0 → e^x = 1 → x = 0. y''(0) = e⁰ = 1 > 0, so it's a min. Min value: y(0) = 1.
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