alleryFor y = x³ - 3x² + 2, find critical points:
Ax = 1
Bx = 0 only
Cx = 0, 2 (y' = 3x² - 6x = 3x(x-2))
Dx = -1, 1
Answer & Solution
Correct answer: C. x = 0, 2 (y' = 3x² - 6x = 3x(x-2))
We have y' = 3x² - 6x.
That is y' = 3x(x - 2).
So y' = 0.
→ x = 0 or x = 2. y'' = 6x - 6. At x = 0: y'' = -6 (max).
At x = 2: y'' = 6 (min).
Keep practising Unit 4-5: Applications of Derivatives & Curve Sketching
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