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Mean Value Theorem says that for continuous f on [a, b] differentiable on (a, b), there exists c ∈ (a, b) with:
Af(c) = 0
Bf(c) = f(a) + f(b)
Cf''(c) = 0
Df'(c) = (f(b) - f(a))/(b - a)
Answer & Solution
Correct answer: D. f'(c) = (f(b) - f(a))/(b - a)
MVT: somewhere the instantaneous slope (f'(c)) equals the average slope (secant). Foundation for many calculus results.
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