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HomeJEE MainMathematicsApplication of Derivatives › For y = sin x, find dy/dx at x = π/3:

For y = sin x, find dy/dx at x = π/3:

Acos(π/3) = 1/2
B1/2
C1
D√3/2
Answer & Solution
Correct answer: A. cos(π/3) = 1/2
dy/dx = cos x. At π/3: cos(π/3) = 1/2. (Equation of tangent at this point: y - √3/2 = (1/2)(x - π/3).)
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