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The distance of the point $(5,12)$ from the origin is

A13
B17
C7
D60
Answer & Solution
Correct answer: A. 13
1. Distance from origin $=\sqrt{5^2+12^2}=\sqrt{25+144}$. 2. $=\sqrt{169}=13$. 3. So the distance is 13 units. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.2_
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