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The area of the triangle with vertices $(0,0)$, $(4,0)$ and $(0,3)$ is

A12 sq units
B7 sq units
C6 sq units
D10 sq units
Answer & Solution
Correct answer: C. 6 sq units
1. Area $=\dfrac12|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|$. 2. $=\dfrac12|0(0-3)+4(3-0)+0(0-0)|=\dfrac12|12|$. 3. $=6$ sq units (a right triangle with base 4, height 3). _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.4_
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