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The distance between the points $(1,2)$ and $(4,6)$ is

A6
B7
C5
D4
Answer & Solution
Correct answer: C. 5
1. Distance $=\sqrt{(4-1)^2+(6-2)^2}=\sqrt{3^2+4^2}$. 2. $=\sqrt{9+16}=\sqrt{25}=5$. 3. So the distance is 5 units. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch7 'Coordinate Geometry', §7.2_
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