alleryIdeal gas equation:
- PV = mR
- PV = RT/n
- P + V = nRT
- PV = nRT
Show answer and solution
Correct answer: D. PV = nRT
PV = nRT.
n = moles, R = 8.314 J/(mol K).
Combines Boyle (P ∝ 1/V at const T), Charles (V ∝ T at const P), Avogadro (V ∝ n).
JEE Advanced Kinetic Theory of Gases — practice questions
Explore 32 free Kinetic Theory of Gases questions in JEE Advanced Physics. Open each question or exercise to read its content, reference answers and available explanation.
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Ideal gas equation:Read the answer and worked solution →Postulate of kinetic theory: gas molecules:Read the answer and worked solution →Avogadro's number:Read the answer and worked solution →R / N_A =Read the answer and worked solution →Root-mean-square speed of gas molecules (mass m):Read the answer and worked solution →Average kinetic energy per molecule (monatomic gas):Read the answer and worked solution →Degrees of freedom for monatomic gas (e.g., He, Ar):Read the answer and worked solution →Most probable speed v_mp:Read the answer and worked solution →Average speed v_avg of molecules:Read the answer and worked solution →Maxwell speed distribution is:Read the answer and worked solution →Internal energy of n moles of ideal gas (monatomic):Read the answer and worked solution →Ratio of specific heats γ for monatomic gas:Read the answer and worked solution →For ideal gas, C_p - C_v =Read the answer and worked solution →Two gases of molar masses M₁ and M₂ at same T. Ratio of v_rms:Read the answer and worked solution →Find v_rms of O₂ at 300 K (M = 32 g/mol, R = 8.314):Read the answer and worked solution →Graham's law of effusion: rate of effusion ∝Read the answer and worked solution →For Maxwell-Boltzmann distribution, fraction of molecules with KE > E behaves as:Read the answer and worked solution →Boyle's law derivation from KTG: at constant T, doubling V causes:Read the answer and worked solution →For monatomic ideal gas, U/T (heat capacity at const V) per mole:Read the answer and worked solution →In adiabatic process for ideal gas:Read the answer and worked solution →For mixture of two ideal gases, total pressure = (Dalton's law):Read the answer and worked solution →Equipartition: at temperature T, each quadratic DOF carries energy:Read the answer and worked solution →Mean free path doubles when:Read the answer and worked solution →At what temperature does v_rms of H₂ equal v_rms of O₂ at 300 K?Read the answer and worked solution →For diatomic gas at very high T (vibrational modes active), DOF = ?Read the answer and worked solution →Boltzmann's distribution gives fraction of molecules in energy state E:Read the answer and worked solution →During adiabatic compression of ideal gas:Read the answer and worked solution →For an ideal gas in adiabatic process: TV^(γ-1) =Read the answer and worked solution →Kinetic energy per molecule of monatomic gas at 300 K (k = 1.38 × 10⁻²³):Read the answer and worked solution →Two containers, equal volume, one with H₂ and one with O₂ at same T, P. Ratio of:Read the answer and worked solution →
Worked practice questions
Postulate of kinetic theory: gas molecules:
- Have fixed positions
- Are in random rapid motion; collisions are elastic
- Are stationary
- Stick together
Show answer and solution
Correct answer: B. Are in random rapid motion; collisions are elastic
KTG postulates: (i) large number of identical molecules in random motion
(ii) elastic collisions (KE conserved)
(iii) negligible molecular volume
(iv) no inter-molecular forces (except during brief collisions).
Avogadro's number:
- 6.022 × 10²³ /mol (number of particles per mole)
- 10⁶
- 13.6
- 9.8
Show answer and solution
Correct answer: A. 6.022 × 10²³ /mol (number of particles per mole)
N_A = 6.022 × 10²³ /mol.
1 mole = N_A elementary entities (atoms, molecules, ions).
Foundation of stoichiometry; relates micro to macro.
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