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For Maxwell-Boltzmann distribution, fraction of molecules with KE > E behaves as:

Aexp(-E/kT) (Boltzmann factor)
BConstant
CLinear in T
DE²
Answer & Solution
Correct answer: A. exp(-E/kT) (Boltzmann factor)
Fraction with KE > E roughly ∝ exp(-E/kT). Higher T → larger fraction above any threshold. Foundation of Arrhenius rate law (chemical kinetics): k ∝ exp(-Ea/kT).
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