Home › JEE Main › Physics › Kinetic Theory of Gases › Boyle's law derivation from KTG: at constant T, …
Boyle's law derivation from KTG: at constant T, doubling V causes:
AP unchanged
BP halves (P ∝ 1/V from PV = nRT at const T)
CP × 4
DP doubles
Answer & Solution
Correct answer: B. P halves (P ∝ 1/V from PV = nRT at const T)
PV = nRT. At const T: P ∝ 1/V. Doubling V halves P. From KTG: doubling V at const T = same N molecules in 2× volume → half the collision rate → half pressure.
Related questions
Speed of sound in ideal gas:For ideal gas, molar heat capacity C_v vs C_p relationship:Two containers, equal volume, one with H₂ and one with O₂ at same T, P. Ratio of:Kinetic energy per molecule of monatomic gas at 300 K (k = 1.38 × 10⁻²³):For an ideal gas in adiabatic process: TV^(γ-1) =During adiabatic compression of ideal gas:Boltzmann's distribution gives fraction of molecules in energy state E:For diatomic gas at very high T (vibrational modes active), DOF = ?