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Boyle's law derivation from KTG: at constant T, doubling V causes:
AP unchanged
BP halves (P ∝ 1/V from PV = nRT at const T)
CP × 4
DP doubles
Answer & Solution
Correct answer: B. P halves (P ∝ 1/V from PV = nRT at const T)
PV = nRT. At const T: P ∝ 1/V. Doubling V halves P. From KTG: doubling V at const T = same N molecules in 2× volume → half the collision rate → half pressure.
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