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At what temperature does v_rms of H₂ equal v_rms of O₂ at 300 K?
AT_H₂ = 600 K
BT_H₂ = 300 × (M_H₂/M_O₂) = 300 × 2/32 = 18.75 K
CCannot determine
DT_H₂ = T_O₂
Answer & Solution
Correct answer: B. T_H₂ = 300 × (M_H₂/M_O₂) = 300 × 2/32 = 18.75 K
v_rms = sqrt(3RT/M). Setting equal: T_H₂/M_H₂ = T_O₂/M_O₂ → T_H₂ = 300 × 2/32 ≈ 18.75 K. (At 300 K, H₂ moves √16 = 4× faster than O₂.)
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