Home › JEE Advanced › Physics › Kinetic Theory of Gases › Two gases of molar masses M₁ and M₂ at same T. R…
Two gases of molar masses M₁ and M₂ at same T. Ratio of v_rms:
AM₁ + M₂
Bsqrt(M₂/M₁) (lighter gas has higher v_rms)
CM₁/M₂
DM₁ × M₂
Answer & Solution
Correct answer: B. sqrt(M₂/M₁) (lighter gas has higher v_rms)
v_rms ∝ sqrt(T/M). Same T: v₁/v₂ = sqrt(M₂/M₁). So lighter gas (lower M) has higher v_rms. Hence H₂ molecules move faster than O₂ at same T.
Related questions
Molecules in a gas move at speeds of the order of the speed of:Compared with solids, atoms in gases are much:The mean free path in gases is of the order of:Argon is an example of which kind of gas?A gas like argon has which kind of degrees of freedom only?Motion of a body as a whole from one point to another is called:A molecule confined to a plane has how many degrees of freedom?A molecule free to move in space needs how many coordinates?