alleryTwo gases of molar masses M₁ and M₂ at same T. Ratio of v_rms:
AM₁ + M₂
Bsqrt(M₂/M₁) (lighter gas has higher v_rms)
CM₁/M₂
DM₁ × M₂
Answer & Solution
Correct answer: B. sqrt(M₂/M₁) (lighter gas has higher v_rms)
v_rms ∝ sqrt(T/M).
**Same T:** v₁/v₂ = sqrt(M₂/M₁).
So lighter gas (lower M) has higher v_rms.
**Hence H₂ molecules move faster than O₂ at same T.**
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