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Average kinetic energy per molecule (monatomic gas):
A2kT
B(3/2) kT
C(1/2)kT
DkT
Answer & Solution
Correct answer: B. (3/2) kT
For 3 translational degrees of freedom: <KE_trans> = (3/2)kT per molecule. From equipartition: each quadratic DOF contributes (1/2)kT.
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