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Assam CEE JEE Main 2023 Mixed — practice questions

Explore 23 free JEE Main 2023 Mixed questions in Assam CEE Physics. Open each question or exercise to read its content, reference answers and available explanation.

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JEE Main 2023 Mixed questions and exercises with answers

Showing questions 1–23 of 23.

A particle moves in a straight line with velocity v = 4t - t² m/s. The displacement of the particle in the time interval from t = 0 to when v becomes zero again is:Read the answer and worked solution →A block of mass 2 kg slides down a rough incline of 30°. Coefficient of kinetic friction is 0.2. Acceleration of block (g = 10):Read the answer and worked solution →Two particles of mass m and 4m have same kinetic energy. Ratio of their de Broglie wavelengths:Read the answer and worked solution →In Young's double slit experiment, if slit separation is halved and wavelength doubled, fringe width becomes:Read the answer and worked solution →Charge Q is placed at center of a cube. Electric flux through one face:Read the answer and worked solution →In LCR series circuit, at resonance, impedance equals:Read the answer and worked solution →A capacitor of capacitance C is charged to voltage V then connected through a resistor R to an uncharged capacitor of same C. Final voltage across each:Read the answer and worked solution →A wire of resistance R is bent into a circle. Resistance between two diametrically opposite points:Read the answer and worked solution →A particle of mass m moves in circle of radius r with constant speed v. Magnitude of momentum change in half revolution:Read the answer and worked solution →Two satellites of same mass orbit Earth at radii r and 2r. Ratio of their kinetic energies:Read the answer and worked solution →Heat capacity of a body is 200 J/K. Heat required to raise its temperature from 20°C to 50°C:Read the answer and worked solution →For a body in SHM with amplitude A, at displacement x, ratio of KE to total energy:Read the answer and worked solution →Two coherent sources of intensity I and 4I interfere. Maximum intensity in resulting pattern:Read the answer and worked solution →Bohr radius for hydrogen is 0.53 Å. Radius of 3rd orbit:Read the answer and worked solution →Magnetic flux through a coil changes from 5 mWb to 1 mWb in 0.1 s. Induced EMF:Read the answer and worked solution →Work done in stretching wire by 1 mm is W. Work to stretch it by 2 mm (same wire, within elastic limit):Read the answer and worked solution →Photon of wavelength 200 nm strikes metal with work function 2 eV. KE of fastest photoelectron (hc = 1240 eV nm):Read the answer and worked solution →A car travels 100 km at 50 km/h, then 100 km at 100 km/h. Average speed:Read the answer and worked solution →At what temperature does kT equal 1 eV?Read the answer and worked solution →Two resistors 3 Ω and 6 Ω in parallel. Equivalent resistance:Read the answer and worked solution →Specific heat capacity of monatomic ideal gas at constant V:Read the answer and worked solution →Electric field due to infinite plane sheet with surface charge density σ:Read the answer and worked solution →Sound wave intensity I dB scale. 60 dB to 80 dB ratio of intensity:Read the answer and worked solution →

Worked practice questions

A particle moves in a straight line with velocity v = 4t - t² m/s. The displacement of the particle in the time interval from t = 0 to when v becomes zero again is:

  1. 16 m
  2. 8 m
  3. 32/3 m
  4. 16/3 m
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Correct answer: C. 32/3 m

v = 0 at t = 0 and t = 4. Displacement = ∫₀⁴ (4t - t²) dt = [2t² - t³/3]₀⁴ = 32 - 64/3 = 32/3 m.

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A block of mass 2 kg slides down a rough incline of 30°. Coefficient of kinetic friction is 0.2. Acceleration of block (g = 10):

  1. 3.27 m/s²
  2. 5 m/s²
  3. 1.73 m/s²
  4. 2 m/s²
Show answer and solution

Correct answer: A. 3.27 m/s²

We have a = g(sin θ - μ cos θ). That is a = 10(0.5 - 0.2 × √3/2). That is a = 10(0.5 - 0.173). So a = 3.27 m/s².

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Two particles of mass m and 4m have same kinetic energy. Ratio of their de Broglie wavelengths:

  1. 1:1
  2. 4:1
  3. 1:2
  4. 2:1
Show answer and solution

Correct answer: D. 2:1

λ = h/p = h/sqrt(2mKE). Same KE: λ ∝ 1/sqrt(m). λ₁/λ₂ = sqrt(m₂/m₁) = sqrt(4) = 2. Hence 2:1.

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