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Electric field due to infinite plane sheet with surface charge density σ:
Aσ/(2ε₀) (uniform on both sides)
Bσ/ε₀
Cσ/r²
Dσ × ε₀
Answer & Solution
Correct answer: A. σ/(2ε₀) (uniform on both sides)
By Gauss law on cylindrical pillbox: E = σ/(2ε₀) on each side. Field independent of distance. For conductor surface: E = σ/ε₀ outside, 0 inside.
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