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UPCET / UPSEE Current Electricity — practice questions — page 2

Explore 102 free Current Electricity questions in UPCET / UPSEE Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Current Electricity questions and exercises with answers

Showing questions 31–60 of 102.

Resistance R of a conductor is proportional to:Read the answer and worked solution →Two resistors 4 Ω and 12 Ω are in parallel; this combination is in series with 8 Ω. Total resistance:Read the answer and worked solution →Drift velocity v_d is given by:Read the answer and worked solution →In a Wheatstone bridge, BALANCE condition gives:Read the answer and worked solution →A 2 Ω, 4 Ω and 6 Ω resistor are in parallel. Equivalent resistance:Read the answer and worked solution →To convert a galvanometer to a VOLTMETER, connect:Read the answer and worked solution →Three cells of emf 2 V each, internal resistance 0.5 Ω each, are connected in series. Total emf and internal resistance:Read the answer and worked solution →Three identical cells with emf 1.5V and internal resistance 0.6 Ω each are connected in parallel. Find equivalent emf and internal resistance:Read the answer and worked solution →If a wire of resistance R is cut into 4 equal parts and joined in parallel, the new resistance is:Read the answer and worked solution →A potentiometer is a NULL device used to:Read the answer and worked solution →A 10 V battery is connected across a 5 Ω resistor. The current through the resistor is:Read the answer and worked solution →Specific resistivity (ρ) of a conductor depends mainly on:Read the answer and worked solution →An ammeter has 0.1 Ω resistance and 1 mA full-scale current. The shunt needed to extend range to 1 A:Read the answer and worked solution →In a Wheatstone bridge: P = 4Ω, Q = 8Ω, R = 6Ω. For balance, S =Read the answer and worked solution →Five identical bulbs are connected in series across an emf of 100V. Each bulb has resistance 5 Ω. Find total current:Read the answer and worked solution →A 12V battery (internal r = 0.5 Ω) drives current through 5.5 Ω external load. Find power dissipated in EXTERNAL resistor:Read the answer and worked solution →A copper wire of length 1 m and cross-section 1 mm² has resistivity 1.7 × 10⁻⁸ Ω·m. Its resistance is:Read the answer and worked solution →Two batteries with emf E₁ = 4V (r₁ = 1Ω) and E₂ = 6V (r₂ = 2Ω) in parallel. Find equivalent emf:Read the answer and worked solution →A wire of resistance 10 Ω is stretched to double its length without changing volume. Its new resistance:Read the answer and worked solution →Maximum power transfer from a source occurs when external resistance equals:Read the answer and worked solution →In a meter bridge experiment, the null point divides the wire as 30 cm and 70 cm. If known resistance is 6 Ω, the unknown is:Read the answer and worked solution →A resistor carries a current of 2 A when a potential difference of 10 V is applied across it. Its resistance is:Read the answer and worked solution →The SI unit of current density is:Read the answer and worked solution →For a uniform wire of resistance R = ρl/A, the resistivity ρ depends on:Read the answer and worked solution →The power dissipated in a resistor of resistance R carrying a steady current I is:Read the answer and worked solution →The emf of a cell is equal to the potential difference across its terminals when:Read the answer and worked solution →Three resistors of 2 Ω, 3 Ω and 5 Ω are connected in series. The equivalent resistance is:Read the answer and worked solution →Two 6 Ω resistors are connected in parallel. Their equivalent resistance is:Read the answer and worked solution →A cell of emf 2 V and internal resistance 0.1 Ω is connected across a 3.9 Ω resistor. The current in the circuit is:Read the answer and worked solution →A cell of emf 2 V and internal resistance 0.1 Ω drives a current of 0.5 A. Its terminal potential difference is:Read the answer and worked solution →

Worked practice questions

Resistance R of a conductor is proportional to:

  1. Length only (R ∝ l)
  2. Both length and 1/area (R = ρl/A)
  3. 1/Area only
  4. Only resistivity
Show answer and solution

Correct answer: B. Both length and 1/area (R = ρl/A)

R = ρl/A. So R is directly proportional to length l AND inversely proportional to cross-sectional area A. ρ (resistivity) is the material property.

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Two resistors 4 Ω and 12 Ω are in parallel; this combination is in series with 8 Ω. Total resistance:

  1. 20 Ω
  2. 11 Ω
  3. 12 Ω
  4. 8 Ω
Show answer and solution

Correct answer: B. 11 Ω

**Parallel:** (4 × 12)/(4 + 12) = 48/16 = 3 Ω. **Then series with 8:** 3 + 8 = 11 Ω.

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Drift velocity v_d is given by:

  1. eEτ/m
  2. eE/m
  3. mE/(eτ)
  4. eE × m × τ
Show answer and solution

Correct answer: A. eEτ/m

During relaxation time τ, electron accelerates with a = eE/m. We have So v_d = aτ. So So v_d = eEτ/m. Negative direction relative to E (because charge is negative).

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