A cell of emf 2 V and internal resistance 0.1 Ω drives a current of 0.5 A. Its terminal potential difference is:
A0.05 V
B2.00 V
C2.05 V
D1.95 V
Answer & Solution
Correct answer: D. 1.95 V
Terminal voltage V = ε − Ir = 2 − 0.5×0.1 = 1.95 V.
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