alleryA cell of emf 2 V and internal resistance 0.1 Ω is connected across a 3.9 Ω resistor. The current in the circuit is:
A20 A
B2.0 A
C0.5 A
D0.05 A
Answer & Solution
Correct answer: C. 0.5 A
We have I = ε/(R + r).
That is I = 2/(3.9 + 0.1).
That is I = 2/4.
So I = 0.5 A.
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