Three cells of emf 2 V each, internal resistance 0.5 Ω each, are conne…

Question

Three cells of emf 2 V each, internal resistance 0.5 Ω each, are connected in series. Total emf and internal resistance:

Accepted Answer

B. E = 6V, r = 1.5 Ω

**In series:** E_eq = E₁ + E₂ + E₃ = 6V.
We have r_eq = r₁ + r₂ + r₃.
So r_eq = 1.5 Ω.
(Series adds both emf and internal resistance.)

Answer

E = 6V, r = 0.5 Ω

Answer

E = 2V, r = 1.5 Ω

Answer

E = 6V, r = 1/6 Ω

Three cells of emf 2 V each, internal resistance 0.5 Ω each, are connected in series. Total emf and internal resistance: