Three resistors of 2 Ω, 3 Ω and 5 Ω are connected in series. The equivalent resistance is:
A30 Ω
B3.3 Ω
C0.97 Ω
D10 Ω
Answer & Solution
Correct answer: D. 10 Ω
In series the resistances add: R = 2 + 3 + 5 = 10 Ω.
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