Two batteries with emf E₁ = 4V (r₁ = 1Ω) and E₂ = 6V (r₂ = 2Ω) in parallel. Find equivalent emf:
A3.33 V
B10 V
C4.67 V
D5 V
Answer & Solution
Correct answer: C. 4.67 V
For parallel: E = (E₁/r₁ + E₂/r₂)/(1/r₁ + 1/r₂) = (4/1 + 6/2)/(1/1 + 1/2) = (4 + 3)/(1.5) = 7/1.5 ≈ 4.67 V.
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