alleryFive identical bulbs are connected in series across an emf of 100V. Each bulb has resistance 5 Ω. Find total current:
A20 A
B4 A
C0.5 A
D1 A
Answer & Solution
Correct answer: B. 4 A
Series resistance = 5 × 5 = 25 Ω. I = V/R = 100/25 = 4 A.
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