Value of ∫₀^(π/2) sin² x dx:
- π/4 (= ∫(1-cos2x)/2 dx from 0 to π/2)
- 1
- π
- π/2
Show answer and solution
Correct answer: A. π/4 (= ∫(1-cos2x)/2 dx from 0 to π/2)
sin²x = (1-cos2x)/2. ∫₀^(π/2) sin²x dx = (1/2)[π/2 - 0] = π/4.
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Correct answer: A. π/4 (= ∫(1-cos2x)/2 dx from 0 to π/2)
Correct answer: C. 60 (= 6!/(3!2!) since 3 A's and 2 N's)
Correct answer: A. -2 (= 4 - 6)