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Value of ∫₀^(π/2) sin² x dx:

Aπ/4 (= ∫(1-cos2x)/2 dx from 0 to π/2)
B1
Cπ
Dπ/2
Answer & Solution
Correct answer: A. π/4 (= ∫(1-cos2x)/2 dx from 0 to π/2)
sin²x = (1-cos2x)/2. ∫₀^(π/2) sin²x dx = (1/2)[π/2 - 0] = π/4.
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