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Number of arrangements of letters in 'BANANA':
A36
B720
C60 (= 6!/(3!2!) since 3 A's and 2 N's)
D120
Answer & Solution
Correct answer: C. 60 (= 6!/(3!2!) since 3 A's and 2 N's)
6 letters, 3 A, 2 N, 1 B. Total permutations = 6!/(3! × 2! × 1!) = 720/12 = 60.
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