allerySum of first 10 terms of AP with a = 3, d = 2:
A100
B120 (= 10/2 × (2×3 + 9×2) = 5 × 24 = 120)
C60
D105
Answer & Solution
Correct answer: B. 120 (= 10/2 × (2×3 + 9×2) = 5 × 24 = 120)
S_n = n/2 (2a + (n-1)d).
We have S_10 = 5 × (6 + 18).
That is S_10 = 5 × 24.
So S_10 = 120.
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