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Distance from point (1, 2, 3) to plane x + y + z - 6 = 0:
Asqrt(3)
B0 (point lies on the plane)
C6
D1/sqrt(3)
Answer & Solution
Correct answer: B. 0 (point lies on the plane)
1 + 2 + 3 - 6 = 0, so the point satisfies the plane equation and lies on the plane. Distance = 0.
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