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Number of integers between 1 and 100 (inclusive) divisible by 3 or 5:
A53
B33
C20
D47 (33 div by 3 + 20 div by 5 - 6 div by 15 = 47)
Answer & Solution
Correct answer: D. 47 (33 div by 3 + 20 div by 5 - 6 div by 15 = 47)
Divisible by 3: ⌊100/3⌋ = 33. By 5: 20. By 15: 6. Union: 33 + 20 - 6 = 47.
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