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HomeJEE MainMathematicsJEE Main 2023 Mixed › lim_(x→0) (e^x - 1)/sin x =

lim_(x→0) (e^x - 1)/sin x =

A1
B-1
C0
D
Answer & Solution
Correct answer: A. 1
Use Taylor: e^x - 1 ≈ x for small x; sin x ≈ x. Ratio → 1. Also L'Hôpital: e^x / cos x → 1/1 = 1.
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