Number of moles of KMnO₄ required to oxidize 1 mole of Fe²⁺ in acidic solution:
- 2
- 5
- 1/5 (Mn(VII) → Mn(II): 5e⁻ accepted; Fe²⁺ → Fe³⁺: 1e⁻ lost)
- 1
Show answer and solution
Correct answer: C. 1/5 (Mn(VII) → Mn(II): 5e⁻ accepted; Fe²⁺ → Fe³⁺: 1e⁻ lost)
MnO₄⁻ + 5 e⁻ → Mn²⁺. Fe²⁺ → Fe³⁺ + e⁻.
**So 1 MnO₄⁻ oxidizes 5 Fe²⁺ → 1/5 mole KMnO₄ per mole Fe²⁺.**