alleryThe energy of a photon of wavelength $\lambda$ is given by
A$E = hc/\lambda$
B$E = c/h\lambda$
C$E = h/c\lambda$
D$E = h\lambda/c$
Answer & Solution
Correct answer: A. $E = hc/\lambda$
$E = h\nu = hc/\lambda$.
So energy is *inversely* proportional to wavelength.
UV photons are more energetic than visible, which are more energetic than IR.
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