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Electronic configuration of Cr³⁺ (Z = 24):

A[Ar] 3d⁴
B[Ar] 3d³
C[Ar] 3d⁵
D[Ar] 3d⁵ 4s¹
Answer & Solution
Correct answer: B. [Ar] 3d³
**Cr:** [Ar] 3d⁵ 4s¹. Cr³⁺: lose 4s and two 3d → [Ar] 3d³. Three unpaired electrons. Paramagnetic.
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