alleryLight of frequency $\nu = 2\nu_0$ ejects photoelectrons from a metal with threshold frequency $\nu_0$. The maximum KE of the photoelectrons is
A$2h\nu_0$
B$3h\nu_0$
C$h\nu_0$
D$h\nu_0 / 2$
Answer & Solution
Correct answer: C. $h\nu_0$
$KE_{max} = h\nu - h\nu_0 = h(2\nu_0) - h\nu_0 = h\nu_0$.
Keep practising Structure of Atom
Browse all Structure of Atom questions for AP Intermediate 1st Year, or explore more Chemistry topics.
Related questions
NEET · Chemistry · Quantum NumbersIn the photoelectric effect, the kinetic energy of ejected electrons is:The electronic configuration of Cr (Z=24) is an exception, written as:By the AUFBAU principle, the 3d subshell starts filling:Hund's rule states that electrons in degenerate orbitals:Heisenberg's uncertainty principle is most accurately stated as:The de Broglie wavelength of a particle with momentum p is:The energy of the nth orbit in a hydrogen atom (Bohr's model) is: