For first-order reaction with t₁/₂ = 10 min, k =
A1/min
B10/min
C6.93/min
D0.0693/min (= ln2/10)
Answer & Solution
Correct answer: D. 0.0693/min (= ln2/10)
We have k = 0.693/t₁/₂.
That is k = 0.693/10.
So k = 0.0693 /min.
Keep practising Unit 4A1: Types of Chemical Reactions
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