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For coordination compound [Co(NH₃)₅Cl]Br₂, total ions in solution:
A1
B3 (= [Co(NH₃)₅Cl]²⁺ + 2 Br⁻)
C2
D5
Answer & Solution
Correct answer: B. 3 (= [Co(NH₃)₅Cl]²⁺ + 2 Br⁻)
[Co(NH₃)₅Cl]Br₂ → [Co(NH₃)₅Cl]²⁺ + 2 Br⁻. Total 3 ions. (Cl is inside coordination sphere, not free.)
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