alleryThe wave number of a photon of frequency $6 \times 10^{14}\,Hz$ (in vacuum) is
A$5 \times 10^{-7}\,m^{-1}$
B$2 \times 10^{6}\,m^{-1}$
C$2 \times 10^{4}\,m^{-1}$
D$1.8 \times 10^{23}\,m^{-1}$
Answer & Solution
Correct answer: B. $2 \times 10^{6}\,m^{-1}$
$\bar{\nu} = \nu/c = (6 \times 10^{14})/(3 \times 10^{8}) = 2 \times 10^{6}\,m^{-1}$.
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